「每日LeetCode」2021年5月17日

本文最后更新于:2023年3月19日 晚上

Lt1773. 统计匹配检索规则的物品数量

1773. 统计匹配检索规则的物品数量

给你一个数组 items ,其中 items[i] = [type, color, name] ,描述第 i 件物品的类型、颜色以及名称。
另给你一条由两个字符串 ruleKeyruleValue 表示的检索规则。
如果第 i 件物品能满足下述条件之一,则认为该物品与给定的检索规则 匹配

  • ruleKey == "type"ruleValue == type
  • ruleKey == "color"ruleValue == color
  • ruleKey == "name"ruleValue == name

统计并返回 匹配检索规则的物品数量

示例 1:

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输入:items = [["phone","blue","pixel"],["computer","silver","lenovo"],["phone","gold","iphone"]], ruleKey = "color", ruleValue = "silver"
输出:1
解释:只有一件物品匹配检索规则,这件物品是 ["computer","silver","lenovo"] 。

示例 2:

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输入:items = [["phone","blue","pixel"],["computer","silver","phone"],["phone","gold","iphone"]], ruleKey = "type", ruleValue = "phone"
输出:2
解释:只有两件物品匹配检索规则,这两件物品分别是 ["phone","blue","pixel"] 和 ["phone","gold","iphone"] 。注意,["computer","silver","phone"] 未匹配检索规则。

提示:

  • 1 <= items.length <= 10
  • 1 <= type.length, color.length, name.length, ruleValue.length <= 10
  • ruleKey 等于 "type""color""name"
  • 所有字符串仅由小写字母组成

思路

按照题意,根据 ruleKey 决定下标值,然后遍历数组判断值是否相等计数即可。

解答

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/**
* @param {string[][]} items
* @param {string} ruleKey
* @param {string} ruleValue
* @return {number}
*/
var countMatches = function (items, ruleKey, ruleValue) {
let index,
res = 0;
if (ruleKey === "type") index = 0;
else if (ruleKey === "color") index = 1;
else index = 2;
for (const item of items) {
if (item[index] === ruleValue) res++;
}
return res;
};